This may help.Pellet Rifle Swept Volume formula:Rifle bore radius squared x Pi (3.14159) x piston stroke = cubed mm. Convert to cubed centimeter by moving decimal point 3 positions left. Example: HW95L .22 caliber 26 mm Bore radius = 13 squared (1/2 diameter) = 169 mm x Pi (3.14159) = 530.929 x HW95L Stroke 85 = 45,128.9 mm cubed. Convert to CC (cubic centimeter) = 45.128 or 45.13 CC for Swept Volume.FYI & may be in error. I have these numbers for a HW95 BUT I have not measured them.TP size = 3 mm, length = 15 mm, TP volume = .106 cc. HW95 piston bore = 26 mm with stroke of 85 mm. Piston weight = 254 grams.