Quote from: darkcharisma on November 03, 2019, 11:23:10 AMif it spiked to 8000psi. a camera placed next to the built in gauge should be able to catch the spike.The pressure spike and release would occur so fast that the (damped) pressure gauge would not have time to react; at least not all the way to 8000 PSI. If you mean that any upward needle twitch on firing would be sufficient evidence, then maybe. Remember, the (probable) ignition source involves rupturing the burst disc by partially melting it. So, both the ignition trigger for a pressure rise and the escape path that drops the pressure would occur at the same time. A second unheated burst disc, that vents to the outside, would react to such a pressure event, if it were engineered to burst at just over 4000 PSI.
if it spiked to 8000psi. a camera placed next to the built in gauge should be able to catch the spike.
..........................................................I wonder if the Chronograph is getting EMI'd showing a false faster velocity during the electronic trigger and a more realistic slower velocity during the passive (not electrically triggered) burst disc test?
This comes under the heading of "Leave it to Lloyd" to figure out how to test something nobody ever though of.... Well done, buddy.... Bob
Decreasing the plenum to 1/2 cc per FPE will require about a 10% increase in regulator setpoint to make up for the additional pressure drop.... You can see the reason that dump valves seldom exceed 50% of the barrel volume.... the small gain in FPE is usually not worth the extra air used to produce it....
The electrical discharge (400V, 400uF) is triggered by 30KV spark gap.
Is EMI related to the spark voltage or quantity of charge dumped? The spark generating coil must be exceeding 10kV, while the capacitor dumped to initiate the burst disk is operating only at 400 volts. Perhaps the 30 kV trigger is interfering more than Lloyds transformer.Quote from: billzweig on October 26, 2019, 08:47:17 PMThe electrical discharge (400V, 400uF) is triggered by 30KV spark gap.
I am not sure how easy it is importing a gun barrel to Canada.
My reference that it might be considered a firearm relates solely to the BATF definition.... I agree it's an airgun, with the possibility it is getting a boost in power from some form of combustion or heating initiated by the spark in a 4000 psi container.... The fuel could be an oil mist, tiny particles of metal, or even vapourized metal, I don't know, and don't really care....
Some time ago i started building a fairly large capacitor bank that aim planing to use for my rail-gun project.Its consist of 24, 15000uF 400v capacitors for a total energy of 28800 Joules.The capacitors are arranged in 3 parallel banks that are wired in series for 1200v and 40000uF.To test the capacitor bank i decided to build a ElectroThermal Gun.The ETG (ElectroThermal Gun) works by discharging the capacitor bank threw fine aluminium powder and foil inside a chamber.The electric current then heats the aluminium enough to make it evaporate and turn into plasma.When the aluminium turns into superheated plasma it expands and the pressure in the chamber increases, the plasma also heats the air so it expands.The expanding gases then force the projectile down the barrel like a conventional (spud)gun.The ETH have a 12mm smooth-bore barrel that is screwed into a steel chamber with a electrode that goes threw a insulator in the end, the power is then feed into that electrode and threw the aluminium-powder.Some videos.Test shot 1:Test shot 1, Second view:Test shot 2:
Bill, looking at your nicely detailed drawing, I don't understand the air path.... You are probably aware of the necessity of having a plenum (firing chamber) of large enough volume to provide the necessary air for the shot.... In a conventional, regulated PCP, we find that about 1 cc of HPA per FPE you intend the gun to produce is a good value to keep the pressure during the shot from dropping too much.... Decreasing the plenum to 1/2 cc per FPE will require about a 10% increase in regulator setpoint to make up for the additional pressure drop.... This means that high powered PCPs need a very large plenum.... This is why you don't see regulators on many Big Bore PCPs....Dump valves, such as you are building, are slightly different, in that we usually look at the valve volume (HPA to be dumped) as a percentage of barrel volume.... Generally speaking, once the valve volume exceeds half the barrel volume the efficiency goes into the dumper.... You are running a dump chamber about the same as the barrel volume (0.438 x 0.438 x PI/4 x 32) = 4.82 CI = 79 cc.... Here is what happens to the pressure during the shot for a few valve volume percentages, starting with 4000 psi:Valve is twice barrel volume.... pressure at bullet exit = 2667 psi.... average pressure = 3333 psi....Valve equals barrel volume.... pressure at bullet exit = 2000 psi.... average pressure = 3000 psi....Valve 50% of barrel volume.... pressure at bullet exit = 1333 psi.... average pressure = 2667 psi....Valve 25% of barrel volume.... pressure at bullet exit = 800 psi.... average pressure = 2400 psi....If we assume that the average pressure, times the bore area (which is the average force), times the barrel length in feet, divided by 2 (to allow for losses), is the approximate FPE.... we get the potential FPE = (0.438 x 0.438 x PI/4 x 32 / 12 / 2) x average pressure.... which is the barrel volume (in CI) / 24 x avg. press.... Your barrel volume is 4.82 CI, so that divided by 24 is 0.201.... If you had an unlimited plenum, and therefore a constant 4000 psi, that works out to (0.201 x 4000) = 804 FPE.... As the average pressure decreases because you have a limited volume to dump, you get the following....Valve is twice barrel volume, FPE = (0.201 x 3333) = 670 FPEValve equals barrel volume, FPE = (0.201 x 3000) = 603 FPEValve 50% of barrel volume, FPE = (0.201 x 2667) = 536 FPEValve 25% of barrel volume, FPE = (0.201 x 2400) = 482 FPETo determine the approximate efficiency, we divide the potential FPE by the volume of air used, in standard CI, which is the pressure in bar times the valve volume.... We would get the following....Valve is twice barrel volume (9.64 CI x 276 bar) = 2660 CI.... Efficiency is (670 / 2660) = 0.25 FPE/CIValve equals barrel volume (4.82 CI x 276 bar) = 1330 CI.... Efficiency is (603 / 1330) = 0.45 FPE/CIValve 50% of barrel volume (2.41 CI x 276 bar) = 665 CI.... Efficiency is (536 / 665) = 0.81 FPE/CIValve 25% of barrel volume (1.20 CI x 276 bar) = 332 CI.... Efficiency is (482 / 332) = 1.45 FPE/CINow these are only vague approximations, but it lets you see what happens to the FPE and the efficiency as you change the valve volume as a percentage of barrel volume.... I hope that gives you some insight into the volume of the dump reservoir you need, and how changing it will potentially affect the FPE and the efficiency....You can see the reason that dump valves seldom exceed 50% of the barrel volume.... the small gain in FPE is usually not worth the extra air used to produce it....Bob
Quote from: billzweig on November 05, 2019, 08:31:27 PM I am not sure how easy it is importing a gun barrel to Canada.Contact Bob Sterne via PM. As a fellow Canadian, and a custom airgun builder, he probably knows all pertinent laws and channels: https://www.gatewaytoairguns.org/GTA/index.php?action=pm;sa=send;u=2569
Quote from: subscriber on November 04, 2019, 02:00:27 AMIs EMI related to the spark voltage or quantity of charge dumped? The spark generating coil must be exceeding 10kV, while the capacitor dumped to initiate the burst disk is operating only at 400 volts. Perhaps the 30 kV trigger is interfering more than Lloyds transformer.Quote from: billzweig on October 26, 2019, 08:47:17 PMThe electrical discharge (400V, 400uF) is triggered by 30KV spark gap.Speed of a discharge, the rate of current change over time = di/dt, is related to how much EMI is generated. That means the sparkgap circuit IS more likely to generate interference. The ignition coil in the video uses a fast di/dt to generate a high voltage impulse. The resulting spark radiates significant EMI which is nicely shown messin' with the Chrony. Cell phones are designed to send and receive very high frequency EM waves. While they are not bullet-proof to EMI (don't arc directly TO the phone!), they will usually function closer to EMI sources that shut down other less robust electronic devices.I see a similar problem when TIG welding on equipment with electronics attached or nearby. The TIG high frequency arc starter function (basically a small Tesla Coil) has to be disabled or I run the risk of frying some critical electrical controls.