One MOA at 25 yards is .26" CTC and this is with H&N FTT 14.66 gr 5.53mm pellets. The target outer circle is 2" while the inner circle is 1". I believe the holes are touching but I could be wrong anyhoo it is my best group so far.MOA at different ranges, CTC shots25 yards = 0.261850 yards = 0.5236100 yards = 1.0472200 yards = 2.0944300 yards = 3.1416400 yards = 4.1888500 yards = 5.2360800 yards = 8.3776900 yards = 9.42481000 yards = 10.47201 MOA Calculation (MOA = minute of angle)How to calculate the 1 MOA for any target distance or range in inches.1. Calculate the distance or range to the target.2. Convert this number to inches.3. Double this number of inches. (= Diameter of Circle)4. Use Pi, 3.14159 times the number in step 3. (= Circle Circumference)5. Divide this number by 21,600. (Note 21,600 = minutes in a circle, 360 degrees x 60 minutes in one degree = 21,600)This is the 1 MOA in inches for the target at that distance or range.Example:1. 100 yards to target.2. 100 x 3 x 12 = 3600 inches to target.3. 3600 x 2 = 7200 inches. (= Diameter of 100 yard Circle)4. Pi 3.14159 x 7200 = 22,619.448. (= Circle Circumference at 100 yards in inches) 5. 22,619.448/21,600 = 1.04719. (= 1 MOA at 100 yards)This number is then rounded to 1.MOA = an angular measurement at a specific distance or range or in layman terms a very small piece or section of the circle circumference.
Chasing/claiming MOA is tricky if you asked me. I haven't found any paper I like that tears well. My 97k has come "close enough" at 25 and 50 a few times I'd claim it CAN shoot MOA...me on the other hand.
HW50 .22 - 5 shots MOD (minute of dime) at 50 yards, probably about as good as I can do, gun can do better.Old dead tree for a target
Nice writeup Hector.The question I have is, what exactly is the deflection? 0.001" at an extreme? This would be a low velocity round nose pellet I imagine. Is it pertinent to us in any way doing what we are doing here? A high percent mullen could not, in any case, divert a pellet of any nose design enough to skip and give erroneous group sizes without leaving a skid-mark.If this skid-mark was not long/large enough to see with the naked eye, the resultant error would prove irrelevant to us here in our competitions, in my opinion.