Scot,At whatever yardage I'm at how would I find the moa for the amount of inches im off at that give distance? Ex: 2 inches off at 75 yds equates to how many moa?Sorry if I'm not understanding correctly.
Quote from: prosportfan on February 09, 2019, 11:24:13 AMScot,At whatever yardage I'm at how would I find the moa for the amount of inches im off at that give distance? Ex: 2 inches off at 75 yds equates to how many moa?Sorry if I'm not understanding correctly.2" x (100yd/75yd)/1.047"perMOA = 2.55moa
Quote from: Scotchmo on February 09, 2019, 03:40:56 PMQuote from: prosportfan on February 09, 2019, 11:24:13 AMScot,At whatever yardage I'm at how would I find the moa for the amount of inches im off at that give distance? Ex: 2 inches off at 75 yds equates to how many moa?Sorry if I'm not understanding correctly.2" x (100yd/75yd)/1.047"perMOA = 2.55moaHere are the reduced formulas that should make it easier:INCHES = POI in inchesYARDS = distances to target in yardsMOA = minutes of angle (shown on reticle)INCHES/YDS x 95.5 = MOAINCHES/MOA x 95.5 = YARDS (use targets size and reticle MOAs to range target)MOA x YDS x 0.0104 = INCHESEdit: What we are really talking about is a right triangle. INCHES is the OPPosite side. YARDS is the ADJacent side. And MOA is the included angle.